Swift
- functions
- function parameter names
- return one value & return multiple values
- call function without explicit parameter name
Define functions
We need to write the parameter name as part of the function call. This isnβt common in other languages, but I think itβs really helpful in Swift as a reminder of what each parameter does.
func printTimesTables(number: Int, end: Int = 10) {
for i in 1...end {
print("\(i) x \(number) is \(i * number)")
}
}
printTimesTables(number: 2)
With return value:
func rollDice() -> Int {
return Int.random(in: 1...6)
}
for i in 1...6 {
print("\(i): \(rollDice())")
}
Take a list of int as parameter:
func square(numbers: [Int]) {
for number in numbers {
let squared = number * number
print("\(number) squared is \(squared).")
}
}
square(numbers: [2, 3, 4])
Return an arrary:
func abc() -> [Int] {}
Return a dictionary:
func abc() -> [String: Int] {}
Return a tuple that contains multiple values:
func getUser() -> (firstName: String, lastName: String) {
return (firstName: "John", lastName: "Doe")
}
let user = getUser()
print(user.firstName)
print(user.lastName)
// or
let (firstName, lastName) = getUser()
print(firstName)
print(lastName)
Or:
func getUser() -> (String, String) {
return ("Taylor", "Swift")
}
let user = getUser()
print(user.0)
print(user.1)
Use _
to omit the parameter name:
func isUppercase(_ string: String) -> Bool {
string == string.uppercased()
}
let string = "HELLO, WORLD"
let result = isUppercase(string)
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