How to Get mp3 file's Durations with Python

How to get durations of mp3 files are two ways.
One of them is using mutagen, the other is using pysox.
Each method has its own advantages and disadvantages.

The way using mutagen is lightweight, and faster than the way using pysox.

That's why mutagen just checks ID3 tag of mp3 files. The other hand, pysox seems to check binaries of mp3 files through Sox CLI.

The pysox method allows us to determine the duration without using ID3 information, i.e. to recognize files with invalid ID3 information or files without ID3 information. Using pysox, you can find out the duration of a file without using ID3 information, i.e. you can detect the duration of a file with invalid or no ID3 information.

The mutagen way example

from mutagen.mp3 import MP3

def mutagen_length(path):
    try:
        audio = MP3(path)
        length = audio.info.length
        return length
    except:
        return None

length = mutagen_length(wav_path)
print("duration sec: " + str(length))
print("duration min: " + str(int(length/60)) + ':' + str(int(length%60)))

The pysox way example

note: pysox needs SOX cli.

import sox

def sox_length(path):
    try:
        length = sox.file_info.duration(path)
        return length
    except:
        return None

length = sox_length(mp3_path)

print("duration sec: " + str(length))
print("duration min: " + str(int(length/60)) + ':' + str(int(length%60)))

answer re: How to get the duration of an mp3 file

Jun 24 '20

1

try pyxsox

I tried to use pysox to the audio file which includes this question post

note: pysox needs SOX cli.

how to use it is like this.

import sox
mp3_path = "YOUR STRANGE MP3 FILEPATH"
length = sox.file_info.duration(mp3_path)
print("duration sec: " + str(length))
print("duration min: " + str(int(length/60)) +

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