Simply skip the first paragraph if you want to see the implementation immediately. The first paragraph are event that led to writing this article đ
Not quite long ago, I was laid off in my previous work place. The company was creating a social application however, I used MongoDB for the database which was obviously a terrible choice. But I had the choice then because MongoDB was the only database which I knew about đ. When the tough hour (building the recommendation system) came, they had no other option but to sack me.
I actually loved the experience working there though
So straight to the point.
But before we jump into the query, I want us to understand how the recommendation works.
The system is like a tree with different depth ranging from 1 to infinity but in the post we will use a depth of 3
In the first depth,we pick random users to use as the node. From this node, we return their followers.In the second depth, we simply get followers of users from our first depth result.
3.In the third depth, we also get followers of users from our second depth result.
This is a simple explanation of what we want to implement. By default, MongoDB was not a good option for this type of relationship in social applications.
To achieve this, we will use the Recursive Common Table Expression. The concept here is to be able to iterate through the followers like a tree.
Let us a create a table two tables âusersâ and âfollowersâ and insert values into them,
-- Create a table called users
create table users(
id serial primary key,
username varchar(40)
);
--- Insert some values into the table
insert into users(username)
values('Johnny Cash'),
('Taylor Swift'),
('Sound Sultan'),
('Tuface'),
('Burna Boy');
--- Create a table called followers
CREATE TABLE followers (
id SERIAL PRIMARY KEY,
leader_id INTEGER NOT NULL REFERENCES users(id) ON DELETE CASCADE,
follower_id INTEGER NOT NULL REFERENCES users(id) ON DELETE CASCADE,
UNIQUE(leader_id, follower_id)
);
--- Insert values into this
insert into followers(leader_id, follower_id)
values(4, 1),
(3, 4),
(5, 1),
(2, 5),
(1, 2),
(5, 3)
We will select the first user as our node which is Country music legend âJohnny Cashâ.
We will then use a Recursive Common Table Expression to iterate through the followers of Johnny Cash
with recursive suggestion(leader_id, follower_id, depth) as (
select leader_id, follower_id, 1 as depth from followers
where follower_id = 1 --- This is the value of the particular user which you want to populate the result from (our Node)
union
select followers.leader_id, followers.follower_id, depth + 1 from followers
join suggestion on suggestion.leader_id = followers.follower_id
where depth < 3
)
select distinct users.id, users.username from suggestion
join users on users.id = suggestion.leader_id
Below is a graphical representation of how Recursive Common Table Expression works
In the diagram I tried to explain this using a flow chart. Below is a sample result. The result are recommended users based on followers of Johnny Cash
=========================
| "id" | "username" |
| 4 | "Tuface" |
| 3 | "Sound Sultan" |
| 2 | "Taylor Swift" |
| 5 | "Burna Boy" |
I was able to understand the concept from Stephen Griderâs course on PostgreSQL
If you have any question, feel free to leave a comment and I will respond as soon as possible.
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