This is a simple program in python to detect the odd and even numbers from a list generated when the user gives his/her numbers automatically.
Basically here the logic is if (num %2 == 0)
then it's even or else odd.
def myFunction():
list1 = []
while True:
userInp = input("Enter your number or press q to exit\n")
if userInp == "q":
evens = []
odds = []
for i in range(0, len(list1)):
if int(list1[i]) % 2 == 0:
evens.append(list1[i])
else:
odds.append(list1[i])
print("Your list of numbers: ", list1)
if len(evens) == 0:
print("No even numbers detected.")
else:
print("Even numbers are:", evens)
if len(odds) == 0:
print("No odd numbers detected.")
else:
print("Odd numbers are:", odds)
break
else:
try:
userInp = int(userInp)
if userInp not in list(list1):
list1.append(userInp)
except ValueError:
print("Error: You have entered a non integer or a decimal fraction number.")
if __name__ == "__main__":
myFunction()
Top comments (0)