1971. Find if Path Exists in Graph
Easy
There is a bi-directional graph with n
vertices, where each vertex is labeled from 0
to n - 1
(inclusive). The edges in the graph are represented as a 2D integer array edges
, where each edges[i] = [ui, vi]
denotes a bi-directional
edge between vertex ui
and vertex vi
. Every vertex pair is connected by at most one
edge, and no vertex has an edge to itself.
You want to determine if there is a valid path that exists from vertex source
to vertex destination
.
Given edges
and the integers n
, source
, and destination
, return true
if there is a valid path from source
to destination
, or false
otherwise.
Example 1:
- Input: n = 3, edges = [[0,1],[1,2],[2,0]], source = 0, destination = 2
- Output: true
- Explanation: There are two paths from vertex 0 to vertex 2:
- 0 → 1 → 2
- 0 → 2
Example 2:
- Input: n = 6, edges = [[0,1],[0,2],[3,5],[5,4],[4,3]], source = 0, destination = 5
- Output: false
- Explanation: There is no path from vertex 0 to vertex 5.
Constraints:
1 <= n <= 2 * 105
0 <= edges.length <= 2 * 105
edges[i].length == 2
0 <= ui, vi <= n - 1
ui != vi
0 <= source, destination <= n - 1
- There are no duplicate edges.
- There are no self edges.
class Solution {
public $graph;
/**
* @param Integer $n
* @param Integer[][] $edges
* @param Integer $source
* @param Integer $destination
* @return Boolean
*/
public function validPath(int $n, array $edges, int $source, int $destination): bool
{
$this->graph = array_fill(0, $n, 0);
for ($i = 1; $i < $n; $i++) {
$this->graph[$i] = $i;
}
foreach ($edges as $edge) {
$this->merge($this->find($edge[0]), $this->find($edge[1]));
}
return $this->find($this->graph[$source]) == $this->find($this->graph[$destination]);
}
public function find($a) {
return $this->graph[$a] == $a ? $a : $this->graph[$a] = $this->find($this->graph[$a]);
}
public function merge($a, $b): void
{
$this->graph[$a] = $b;
}
}
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