514. Freedom Trail
Difficulty: Hard
Topics: Array
, Dynamic Programming
, Depth-First Search
, Breadth-First Search
In the video game Fallout 4, the quest "Road to Freedom" requires players to reach a metal dial called the "Freedom Trail Ring" and use the dial to spell a specific keyword to open the door.
Given a string ring
that represents the code engraved on the outer ring and another string key
that represents the keyword that needs to be spelled, return the minimum number of steps to spell all the characters in the keyword.
Initially, the first character of the ring is aligned at the "12:00"
direction. You should spell all the characters in key
one by one by
rotating ring
clockwise or anticlockwise to make each character of the string key aligned at the "12:00"
direction and then by pressing the center button.
At the stage of rotating the ring to spell the key character key[i]
:
- You can rotate the ring clockwise or anticlockwise by one place, which counts as one step. The final purpose of the rotation is to align one of
ring
's characters at the"12:00"
direction, where this character must equalkey[i]
. - If the character
key[i]
has been aligned at the"12:00"
direction, press the center button to spell, which also counts as one step. After the pressing, you could begin to spell the next character in the key (next stage). Otherwise, you have finished all the spelling.
Example 1:
- Input: ring = "godding", key = "gd"
- Output: 4
- Explanation:
For the first key character 'g', since it is already in place, we just need 1 step to spell this character.
For the second key character 'd', we need to rotate the ring "godding" anticlockwise by two steps to make it become "ddinggo".
Also, we need 1 more step for spelling.
So the final output is 4.
Example 2:
- Input: ring = "godding", key = "godding"
- Output: 13
Constraints:
-
1 <= ring.length, key.length <= 100
. -
ring
andkey
consist of only lower case English letters. - It is guaranteed that
key
could always be spelled by rotatingring
.
Solution:
Here's a breakdown of how we approach it:
Problem Understanding
We are given two strings:
-
ring
: the circular ring of characters. -
key
: the word we need to spell by rotating the ring.
For each character in key
, we rotate the ring
to align the character at the top (index 0
), and this rotation can happen either clockwise or anticlockwise. The goal is to find the minimum number of rotations (steps) required to spell all the characters of key
.
Steps for the Solution
-
Character Positions:
- First, we precompute the positions of each character in
ring
. This allows us to efficiently look up all positions where a given character appears.
- First, we precompute the positions of each character in
-
Dynamic Programming Table:
- Let
dp[i][j]
represent the minimum number of steps required to spell the firsti
characters ofkey
, ending withkey[i-1]
aligned at positionj
inring
.
- Let
-
Base Case:
- For the first character of
key
, we initialize the DP table by calculating the steps needed to rotatering
to alignkey[0]
with index0
.
- For the first character of
-
State Transition:
- For each character in
key
, we iterate through all positions inring
where this character occurs. For each such position, we compute the minimum steps to move from every possible position of the previous character inkey
. The rotation can happen clockwise or anticlockwise, and we take the minimum steps needed for this transition.
- For each character in
-
Final Answer:
- After processing all characters in
key
, the answer will be the minimum number of steps to spell the last character ofkey
from any possible position inring
.
- After processing all characters in
Let's implement this solution in PHP: 514. Freedom Trail
<?php
class Solution {
/**
* @param String $ring
* @param String $key
* @return Integer
*/
function findRotateSteps($ring, $key) {
...
...
...
/**
* go to ./solution.php
*/
}
}
// Test cases
$solution = new Solution();
echo $solution->findRotateSteps("godding", "gd") . "\n"; // Output: 4
echo $solution->findRotateSteps("godding", "godding") . "\n"; // Output: 13
?>
Explanation:
-
Preprocessing:
- We create an array
$char_positions
where the key is a character, and the value is an array of all indices inring
where this character occurs. This helps in efficiently finding positions of each character when needed.
- We create an array
-
Dynamic Programming Table Initialization:
- For the first character of
key
, we initialize the DP table by calculating how many steps are required to move the first character ofkey
to the top position (0
index ofring
).
- For the first character of
-
DP Table Filling:
- For each character in
key
, we compute the minimum number of steps required to move from the previous character's positions to the current character's positions, updating the DP table with the minimum steps.
- For each character in
-
Result Extraction:
- After processing all characters in
key
, the result is the minimum number of steps found in the last row of the DP table.
- After processing all characters in
Time Complexity
- Precomputing the character positions takes O(n), where
n
is the length ofring
. - The DP solution iterates through each character in
key
and for each character, it checks all possible positions inring
, resulting in O(k * m^2) complexity, wherek
is the length ofkey
andm
is the number of positions of each character inring
.
Thus, the solution efficiently handles the problem's constraints and gives the correct minimum steps to spell the key
.
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